port load cap计算的问题
时间:12-12
整理:3721RD
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timing的报表如下:
****************************************
Report : timing
-path_type full
-delay_type max
-input_pins
-nets
-max_paths 1
-capacitance
Design : top_pad
Version: B-2008.12-SP3
Date : Mon Jul 4 21:48:43 2011
****************************************
Startpoint: top_core/sdr_ctr2/sdr_sel_d_reg
(rising edge-triggered flip-flop clocked by pll_out)
Endpoint: sdr_dq_p[0]
(output port clocked by pll_out)
Path Group: pll_out
Path Type: max
Point Fanout Cap Incr Path
-----------------------------------------------------------------------------
clock pll_out (rise edge) 0.00 0.00
clock network delay (ideal) 4.00 4.00
top_core/sdr_ctr2/sdr_sel_d_reg/CK (DFFSQX2M) 0.00 4.00 r
top_core/sdr_ctr2/sdr_sel_d_reg/Q (DFFSQX2M) 0.81 * 4.81 f
top_core/sdr_ctr2/sdr_sel_d (net) 2 0.03
top_core/sdr_ctr2/sdr_sel_d (sdr_ctr_0) 0.00 * 4.81 f
top_core/n27 (net)
top_core/U24/A (BUFX2M) 0.00 * 4.81 f
top_core/U24/Y (BUFX2M) 0.34 * 5.15 f
top_core/sdr_sel_dq (net) 4 0.05
top_core/sdr_sel_dq (top_core) 0.00 * 5.15 f
sdr_sel_dq (net)
U57/A (BUFX2M) 0.00 * 5.15 f
U57/Y (BUFX2M) 0.40 * 5.55 f
n58 (net) 5 0.06
U55/A (BUFX2M) 0.00 * 5.55 f
U55/Y (BUFX2M) 0.30 * 5.85 f
n50 (net) 2 0.03
U39/A (BUFX2M) 0.00 * 5.85 f
U39/Y (BUFX2M) 0.64 * 6.49 f
n49 (net) 2 0.16
pad12/OEN (PB8) 0.00 * 6.49 f
pad12/PAD (PB8) 0.94 * 7.43 r
sdr_dq_p[0] (net) 1 12.38
sdr_dq_p[0] (inout) 0.00 7.44 r
data arrival time 7.44
clock pll_out (rise edge) 10.00 10.00
clock network delay (ideal) 4.00 14.00
clock uncertainty -0.30 13.70
output external delay -4.00 9.70
data required time 9.70
-----------------------------------------------------------------------------
data required time 9.70
data arrival time -7.44
-----------------------------------------------------------------------------
slack (MET) 2.26
1
上面的STA报表中,sdr_dq_p[0] (net) 电容为12.38,其中set_load设置了8,PB8/PAD自身的电容为4.37,剩下的0.01是怎么来的?在design的所有output port均有这个0.01不知道是怎么加上去的?有什么命令可以查看这个计算过程吗?或者可以解释这个0.01的出处?多谢!
****************************************
Report : timing
-path_type full
-delay_type max
-input_pins
-nets
-max_paths 1
-capacitance
Design : top_pad
Version: B-2008.12-SP3
Date : Mon Jul 4 21:48:43 2011
****************************************
Startpoint: top_core/sdr_ctr2/sdr_sel_d_reg
(rising edge-triggered flip-flop clocked by pll_out)
Endpoint: sdr_dq_p[0]
(output port clocked by pll_out)
Path Group: pll_out
Path Type: max
Point Fanout Cap Incr Path
-----------------------------------------------------------------------------
clock pll_out (rise edge) 0.00 0.00
clock network delay (ideal) 4.00 4.00
top_core/sdr_ctr2/sdr_sel_d_reg/CK (DFFSQX2M) 0.00 4.00 r
top_core/sdr_ctr2/sdr_sel_d_reg/Q (DFFSQX2M) 0.81 * 4.81 f
top_core/sdr_ctr2/sdr_sel_d (net) 2 0.03
top_core/sdr_ctr2/sdr_sel_d (sdr_ctr_0) 0.00 * 4.81 f
top_core/n27 (net)
top_core/U24/A (BUFX2M) 0.00 * 4.81 f
top_core/U24/Y (BUFX2M) 0.34 * 5.15 f
top_core/sdr_sel_dq (net) 4 0.05
top_core/sdr_sel_dq (top_core) 0.00 * 5.15 f
sdr_sel_dq (net)
U57/A (BUFX2M) 0.00 * 5.15 f
U57/Y (BUFX2M) 0.40 * 5.55 f
n58 (net) 5 0.06
U55/A (BUFX2M) 0.00 * 5.55 f
U55/Y (BUFX2M) 0.30 * 5.85 f
n50 (net) 2 0.03
U39/A (BUFX2M) 0.00 * 5.85 f
U39/Y (BUFX2M) 0.64 * 6.49 f
n49 (net) 2 0.16
pad12/OEN (PB8) 0.00 * 6.49 f
pad12/PAD (PB8) 0.94 * 7.43 r
sdr_dq_p[0] (net) 1 12.38
sdr_dq_p[0] (inout) 0.00 7.44 r
data arrival time 7.44
clock pll_out (rise edge) 10.00 10.00
clock network delay (ideal) 4.00 14.00
clock uncertainty -0.30 13.70
output external delay -4.00 9.70
data required time 9.70
-----------------------------------------------------------------------------
data required time 9.70
data arrival time -7.44
-----------------------------------------------------------------------------
slack (MET) 2.26
1
上面的STA报表中,sdr_dq_p[0] (net) 电容为12.38,其中set_load设置了8,PB8/PAD自身的电容为4.37,剩下的0.01是怎么来的?在design的所有output port均有这个0.01不知道是怎么加上去的?有什么命令可以查看这个计算过程吗?或者可以解释这个0.01的出处?多谢!