微波EDA网,见证研发工程师的成长!
首页 > 研发问答 > 微波和射频技术 > 天线设计和射频技术 > How can we do impedance matching of RF Gilbert Mixers differential output?

How can we do impedance matching of RF Gilbert Mixers differential output?

时间:04-09 整理:3721RD 点击:
How can we do impedance matching of a differential output of an RF Gilbert Mixers
Thinks

Match to which load? single end or differential?
Load value?
And Output Mixer impedance?
At which Frequency?
I think some info are missing..

Mazz

Explain your mixer completely with the load?
Do you want input matching to a LNA or Output matching to a load

Up or down convert mixer?

Match to which load? single end or differential?
Load value?
And Output Mixer impedance?
At which Frequency?
I think some info are missing..

Mazz



I would like to mach the differential mixer output to the 50 Ohm load and the differential input to 50 Ohm olso, for exemple the Rf input at 5GHz and the IF output at very low frequency ~~ 100kHz

any one can help me, it is urgent

The input match circuit have to be designed starting from the input impedance of your circuit. Without this information, no help can be given.
For output, usually, being the freq very low, there is no need to match it, a simple voltage conversion & buffer from differential to single end is OK.
Mazz

think you mazz,

I am a new RF DEsigner so can you give me an exemple of an buffer converter from differential to single end.

An other question : can I let the output differential and work like this without the single end conversion.

And Using ADS of Agilent I can't Design a Mixer at zeros IF frequency it apear a warning message talling '' IF Output can't be DC'' why?

Think you very much mazz you are very helpfull

Analog Devices AD8130 is suited for differential to single end conversion up to MHz range.

You ZIF downconverter has a spectral content in the near zero Bandwidth at the mixer output, from 0 to BW/2. So you can simulate your circuit using LOfreq and RFfreq in the range of LOfreq-BW/2..LOfreq+BW/2.
The simulator gives the warning because you will not be able to distinguish the DC lavel due to circuit polarization from the signal.
I hope it can help.
Mazz

Copyright © 2017-2020 微波EDA网 版权所有

网站地图

Top