loaded-line phase shifter
The only way I know uses some form of reflection network like a branch line coupler. The signal goes in one input and out the other input. The load on one of the outputs is selected or not by the PIN diode.
That actually needs two PIN diodes:(
why do you use the difference or integrate amplifier
conventionally there are required, at least, either two diodes per bit (reflection and loaded-line type) or four diodes per bit(switched line).
I've found a paper (MW and Optical technology letters vol 14 no.2 1997) which makes the analysis with a single diode per bit and compares with a loaded-line type). maybe it is useful to you, but i think that both in match and bandwidth response, conventional ones behave much better
Thanks for the info. I will try to find it out. But for the time being can you please tell one or two sentences about the method they have suggested if you can remember them.
Have a nice time,
better than that, here you have it
regards
dowjones,
It is really a nice paper. Thank you very much and really appreciate your efforts.
g86
In a -3 dB hybrid coupler, if a mismatched load at the output port 1 (e.g. -15 dB) and the same load at the output port 2... how much is the matching at the input port and the matching at the load port?
I want to compare my considerations with yours.
Regards
Lupin
:D Hi,
In a High\low filter network you can use a single pin diode do the 90 degree phaseshift.I have do it as 90 45 22.5 and so on.
H jamez,
I want to know little bit more. Can you please...
regards,
