微波EDA网,见证研发工程师的成长!
首页 > 研发问答 > 微波和射频技术 > 天线设计和射频技术 > am to pm conversion

am to pm conversion

时间:04-11 整理:3721RD 点击:
Could anyone please tell me what does these spec. mean?

AM/AM conversion--Typ:8% , Max:12%
Conditions:5<Pout<34dBm; 6.5% AM modulation with fmod=67kHz at Pin

AM/PM conversion--4deg/dB
Conditions:-0.5<Pin<0.5dBm, 5<Pout<34dBm;


Regarding AM/AM conversion, what does %8 mean?
Regarding AM/PM conversion, what does 4deg/dB mean?
Thanks.

AM/PM is easy. Hook the beast to a vector network analyzer, with some means to monitor output power (directional coupler and power meter between output and netwrk analyzer). Set output power to 5 dBm, read phase, increase output power to 6 dBm, read phase. If the phase difference is < 4 degrees, you are in-spec. Now redo with power at 6 dBm, increase to 7 dbm, is phase difference is <4 dBm...repeat until you are at 34 dBm. You will find the most trouble around the 1dB compression point.

As to the AM/AM, they are talking about how much the gain compresses vs output power. Not quite sure what the % means though.

Copyright © 2017-2020 微波EDA网 版权所有

网站地图

Top