POWER INCIDENT& REFLECT VS REFLECTION CO EFFICIENT

HELLO,ALL
GIVE THE RELATION BETWEEN POWER INCIDENT,POWER REFLECTION & VOLTAGE REFLECTION CO-EFFICIENT.

EXAMPLE:
INCIDENT POWER :30dBm,
REFLECTED POWER:20dBm,
INPUT & CHARACTERISTIC IMPEDENCE:50 ohm,

WHAT IS THE LOAD IMPEDENCE & VOLTAGE REFLECTION CO-EFFICIENT?

Γ = SQRT [(Power_ref_watt)/(Power_inc_watt)]

To transform dBm in watts:
Power_watt = [10^((Power_dBm)/10)]/1000

For more information read this tutorial from Agilent:
http://na.tm.agilent.com/pna/help/PN...asurements.htm

Pi= 30 dBm, Pr=20 dBm, Pi-Pr=10dB
10 dB=> Γ=0.10/2 = Z0-ZL/(Zo+ZL)=0.05
=> ZL=Z0(1+Γ)/(1-Γ) = Z0(1.05)/(0.95)=55.26 ohm
VSWR=(1+Γ)/(1-Γ)=(1.05)/(0.95)=1.11

thank you.

If Incident_Power = 1W (30dBm) and Reflected_Power = 0.1W (20dBm), results that Γ = 0.32
If Γ = 0.32 => VSWR = 1.92

THANK YOU,
vfone.
U R GIVEN THE EXAMPLE IN WATTS,THAT IS MORE USEFULL.