lin mag

Hi all,

Anyone know how to convert from 'LIN MAG' to 'LOG MAG'?

Thanks in advance.

use the exponential property of bipolar devices

Depends. If you are measuring voltages or phase noises, use 'Log mag' = 20 Log ('Lin Mag').

If you are measuring power, 'Log Mag' = 10 Log ('Lin Mag')

Ex: 0.1 mW is the same as 10 Log (0.1 mw/1 mw) = -10 dBm

or
0.2 volts is the same as 20 Log (0.2v/1 v) = -13.9 dbv

Have you tried dB() function?

I think there is something wrong. Measuring power is 20log().
Measuring voltages is 10log().

I think there is something wrong. Measuring power is 20log().
Measuring voltages is 10log().