What's the formula for finding the Shannon limit?

Can I know how to find a Shannon limit, if I am using BPSK and Coding rate-1/2. Is there any specific formula to find it?Thx.

C=BW*log2(1+S/N), this is the Shannon limit, if consider the codec gain, you should reference to the "digital communication handbook"

hi
i didnt undrestand your questions , but if you are looking for amethod to determine the maximum data rate possible on a channel , then there is agood paper by Blahaut that he develops one of the only two algrithemes that can measure the channenl bandwidth and data rate( practical values) ...


Best Regards

If I am using BPSK with coding rate of 1/2, and I am looking for the SNR values. So, what should I assume with the bandwidth in C=BW*log2(1+S/N). I read some of the text book saying that, shannon limit for such coding rate and BPSK is 0.188 dB. How should I apply it? Is it 0.5=BW*log2(1+s/N)?

what is 0.188 dB? SNR or energy per bit(Eb/N0)? What the text book do you read? The shannon limit is -1.6 dB (Eb/N0) regardless modulation schemes. Also the rate 1/2 is a rate for BSC channel whose the maxmimum capacity is one. This is in the different part of the system.