measurement of peak to average

Hi,

I dont quiet understand the definition of peak to average ratio.

Suppose my DAC outputs a signal with 10dB peak to average.
If I measure the signal on the oscilloscope, will I see the peak signal 3.16 times (10dB) higher then the rms signal?

example:
Rms = 0.1V
Peak to Peak = 1V ===> Peak = 0.5V
-------
PAR=20*log10(0.5/0.1)=13.96dB

But from RF power prespective:

Prms ~ (0.1V)^2
Ppeak ~ (0.5V/sqrt(2))^2
-------------
PAR=10*log10{[(0.5V/sqrt(2)]^2 / [(0.1V)^2]}


---> PAR= 10.96dB


Can someone please clarify this issue?

Appriciate the answer,
Jimmy

Hi
This is true:
Prms ~ (0.1V)^2
Ppeak ~ (0.5V)^2
-------------
PAR=10*log10{[(0.5V]^2 / [(0.1V)^2]}=13.96dB


regards