power dissipation of frequency divider

Hi,

May I know how to determine power dissipation of the frequency divider (divide by 2 using 2 DFF)? Since the V and I of the frequency divider always change with time.

Thanks.

get the waveform of the current , and u have constant voltage source which is VDD

khouly

You're kidding, right?

y , he can get from the current waveform the RMS current , and he have the supply voltage
check ads simulation about power dissipation in dividers ,
specialy it is done if it is not static divider

biff if u have another method can u tell me , how to do it ?

khouly

Yeah, while it is clocking at the frequency of interest you look at the power supply voltage and the average power supply current and you multiply them together!