antenna calc

hi to everyone
iam using the following RF(FM-RRF1 433c) module of www.okwelectronics.com

for our telemetry project....
the antenna specification that is mentioned in datasheet
by manufacturer for RX and TX
is as

1_ 34 Turns of enamelled copper wire diameter 0.5mm
close wound on 2.5mm diameter former
for helical antenna

2- Loop Antenna Area
4 To 10cm2 for loop antenna

3- 17.3cm @ 433MHz for wipe antenna

my question is that by which formula and conditions
Q1-the loop area (4_10cm^2) of antenna is calculated
as we know that the area of loop antenna S = N*pi*row^2 loop area
Q2-
By which factor 34 turn of 0.5mm diameter of copper wire is selected

i dont know...try to send simple questions

The size of an antennna always is proportional to
the frequency. So the area of the loop determine
the frequency at which the antenna will work.
Q2: usually the number of turns has to deal with
impedance of the antenna.

thx for reply but
dear as i have mentioned above the tx frequency is 433M then u calculate the area of loop antenna ,
more over i have read the book "element of electromegntic " by mno sadiko 2nd edition , about antenna topic ..iam fail to find out the exact area of the Loop antenna that is above mentoned at this frequncy 433M