What is the best matching condition to a non-50 Ohm load ?

Hi,

I have a power amplifier which drive a non-50 Ohm load(around 10-10j Ohm measured by VNA, from 10~100MHz) in my system.
I would like to do some impedance matching between PA and the load.
Before this, I would like to know how do I judge the "matching condition" to the load ? Could I measure the peak-to-peak voltage on the load to determine the matching condition ?
Or, if I matched the load to 50 Ohm by using some capacitor or inductors, does it mean the best power delivery from PA to load whatever the combination of capacitor/inductor is ?

Thanks.

Yes, match the 10-j10 load to the same impedance the amplifier is designed for. Either 50 or 75 ohms.

see: https://www.edaboard.com/ftopic387895.html
for how to do this.

You will be able to do this easily enough over a narrow band but not over a decade range of frequencies.

For maximum efficiency, the source impedance is much lower (voltage source) or much higher (current source) than the load. Maximum gain is of no consequence. Earlier stages are the place to make the gain higher.

The load won't have the said impedance over the full 10 to 100 MHz range. (Near to technically impossible). You also didn't tell, if
the PA is standard 50 ohm or different.

A VWSR instrument is the best method to check the matching condition over the full frequency range.

Hi all,

Thanks for your reply.

The thing I want to be sure is(assume PA output impedance is perfect 50Ohm) :

If I matched the load to pefect 50Ohm, does it mean the best power delivery to the load(actually the real part of the load) no matter what the combination of matching network is ?

Thanks again.