TM10 standing wave in a waveguide with some obstacles

I would like to create a 150 MHz standing wave in a 1m x 1m x 8m waveguide, or rather a cuboid box. In the antinodes, in the center of the cross section of the waveguide I want to place 0.3m x 0.3m x 0.3m cubes filled with small resonant loop receiving antennas (2 cm side length, 3 cm spacing between the centers of the loops).
If you have any pointers - how to excite the standing wave, what problems will be caused by the ensembles of resonant antennas - please respond.

The cuttoff frequency for a 1 x 1 meter crossection waveguide is 149.9 MHz, so trying to run it at 150 MHz is not a good idea. If that is the frequency it has to run at, you will want a bigger crossection than 1x1 meter!

Once you get the a x b dimensions right in the waveguide, calculate the guide wavelength, and make the length some integer N wavelengths long. Then in practice you will need to make some small modifications to the length to resonate at exactly 150 MHz--maybe make one of the waveguide ends slightly moveable. If you are just a little off, bending the center of the >1x1 meter end plate will make it change the effective length a little.

In industry is is common practice, thought, to NOT make the dimensions a=b, but to make one bigger than the other. That will keep the modes in one orientation, such as TM10, instead of letting TM01 modes start propagating. Things like inserting loop couplers in the middle could take a TM10 mode and start making it look like a TM01 mode.

How were you planning on connecting the loop antennas to the outside world? You can not simply run a coax cable in to them, as that will totally screw up the fields inside of the waveguide (the coax line will look to the waveguide as a shorted post). This will, as a minimum, perturb the resonant frequency.

There are ways around this. You might want a loop antenna with a small converter from detected power to optical light, and run the light out a fiberoptic cable, for instance. The fiberoptic cable, being non-metalic, will not perturb the field much.

It would help if you told us something about what you are trying to do.

I need to draw considerable power from the receiving antennas, either as VHF or as DC - I can rectify it right by the antennas using proper Schottky diodes.
I think I can connect antennas to the outside world by using twin lead made of thin wires - I can use low currents.
Also, there is a fundamental issue that I do not understand: in the TM10 mode omega10 = omega and the group velocity of the waves should be zero. What do you say to that?

I am not sure what you mean by omega 10 = omega. Maybe you were writing in a different language and this website translated it weirdly. Do you mean the wavelength?

I assure you that the group velocity is non-zero! It is something around the speed of light.

If you need to get power out of the system, the easiest way would be to just insert an e-field probe into an Electric Field maximum point, and go out the top or bottom wall of the waveguide. You can use a coaxial connector at the top or bottom wall, with the outer sheild of the coax connector attached to the waveguide wall, and the E-field probe attached to the coax connector center pin.

I am writing in English. I thought about it and decided that to be above the cut-off frequency I have to have ω > ω10, so the group velocity will be positive.
(I am using symbols like Griffiths, ω = 2*π*f).
Let's say that I use a short dipole transmitting antenna to excite the standing wave. What should I do to maximize the amount of energy in the TM10 mode?
What does an e-field probe look like? Is it a straight wire? I am not sure what it does to the field when I take energy out using it.
In the case of a resonant loop antenna I know how to calculate what happens to the field, and I know that it is acceptable to me.
Also, I do not know what a short dipole receiving antenna does to the field, or how much energy it can take up from a field of known intensity.
If you have any answers or comments, please let me know.