can some one help with single phase bridge rectifier

single phase bridge rectifier has RL=10ohms, the peak supply Vm=170v f=60 try to ind the average output voltage of the rectifier if the sources inductance is negligibl.
i use the formula
Vdc=2Vm/pi === 2(170)/pi ===108.2
get answer of 108 but the book answer was 159.42? can some1 explain?
thanks,

Assuming no more voltage drop other than from 1,2V from diodes and no capacitor, neither of the results is right.

I got:
(170V - 1,2V) / sqrt(2) = 119,36V