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About effective parameters of metamaterials mu=n*z epsilon=n/z

时间:04-07 整理:3721RD 点击:
hi ,i saw the relations that mu=n*z ,epsilon=n/z several times,but i don't know where them come from,and even where they can be used to.
So if here anyone know them ,please be kind to tell me .thanks in advance.

You can determine this relationship very quickly. Note that n = refractive index = sqrt(e_r) and that z = sqrt(mu_0*mu_r/(e_0*e_r)).

Have fun :)

hi
for information about that u can read chapter 1 of metamaterials books by nader engheta and the metamterial book of itoh

hi , tallface65
i have understood this question with u help. thank you very much !

lingzi

---------- Post added at 01:13 ---------- Previous post was at 01:10 ----------

hi ferdows ,
thanks your advice, i have found the book u mentioned. it really helpful .thanks again.
lingzi

just a quick note:
n is not equal to sqrt (e_r); you can simply see that by multiplying sides of both equations: mu*epsilon=n*z*n/z=n^2 => n=sqrt(mu*epsilon). So the correct equation is n = sqrt (e_r*mu_r); however, as mu_r is in most cases very close to 1, most of the times you can assume n=sqrt(e_r); but thats not always the case.

hi
thanks mamali

your explanation is very usefull for me.


lingzi

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