Microstrip Antenna for Wimax Application using HFSS

Hello Everybody,
My Name is Abdelmoniem Mowafak El-Assar, Student at the AAST, Last year, and this subject is my Grad Project.

Actually um having some troubles that i wanna share with u.

1st I've just finished my program for Designing Microstrip Antenna knowing only f ( the desired frequency) & (er & height) for the dielectric material using matlab. with 2 solutions till now (Rectangular Patch and Circular Patch).

that was the results :
for the Circular :
units are in cm , u should multiply by 10 to make it mm
at f=3.5 Ghz, er=4.65 and h=1.5 mm

The radius of the circluar patch :
a =1.0670 cm = 10.67 mm ( in Hfss)
ae =1.1652 cm= 11.652 mm ( the effective )

The Substrate & ground :
Lg =1.9670 but we will take lg= 6.5 cm = 65 mm (in Hfss) ; because Lfeedline + 2*a is larger than the Lg, is that reliable >?
Wg =1.9670 but we will take wg=2.5 cm = 25 mm (in Hfss) ; because Wfeedline + 2*a is larger than the Lg, is that reliable >?

The Feed Line
Lf =4.2000 cm = 42 mm (in Hfss)
Wf =0.2751 cm= 2.751 mm (in Hfss)


L: length
W:width
a:radius
h:hight
f:operating frequency

when i finish my program isa, I'm gonna make it programmed to be like an incredible accurate calculator.
Hope Help

Thanks

hiiii i am need of software matlab code for the circular patch microstrip did u get the code....if yes please post the code as i have to excute in my project seminar for my b.tech

here u r, but plz check it as i think there is a problem in my pc while reading it

Here is the written code, i have done it using matlab, and u will need matlab to trace it and (try and error) till u get the true or real or practical or hfss Circular patch radius..

here it is :
--------------------------- Mando88eg------------------------------
clc;
f=3.5; % desired frequency
z=50; % impedance (usually used 50 ohm or 75 ohm)
l0=3e11/3.5e9;
er=4.65;
h=0.15; % hight of substrate
a=1.067 % try here by inserting different values till ae == ae1
ae1=(8.794)/(f*sqrt(er)) % effective radius
ae=a*sqrt(1+(2*h/(pi*a*er)*((log(a/(2*h)))+(1.41*er+1.77)+(h/a)*(0.268*er+1.65)))) % same effective radius and must be = ae1 to get the true radius a from the equation
lg=6*h+2*a %ground length
wg=lg %ground width
lf=0.49*l0 %feedline length
A=(z/60)*(((er+1)/2)^(1/2))+((er-1)/(er+1))*(0.23+(0.11/er));
wf=(8*h*exp(A))/((exp(2*A))-2) %feedline width

%units are in mm
------------------------------------------------------------

For any question or any explanation, um here for u.

enjoy ur day

there is no document in the rar file that was posted i.e if i open the file there i sno code in that ... can u please post the code once again

Added after 6 minutes:

i am designing the circular patch microstrip antenna for the wifi 2.25ghz range, er=4.4 ,h=1.6mm
... i need a matlab code to find radius,directivity ,gain ,return loss,vswr.... and also can we write a code for the obtaining radiation pattern ?

i am poor at writing the matlab program .... can you please help me out? thanx

That's ur code , and for u I calculated the Circular Patch Radius (a) , and all units are in centimeters. k .

That's the code
----------------------Mando88eg-----------------------

clc;
f=2.25; % desired frequency in Ghz
z=50; % impedance (usually used 50 ohm or 75 ohm)
l0=3e10/3.5e9;
er=4.4;
h=0.16; % hight of substrate in cm
a=1.7519 % try here by inserting different values till ae == ae1
ae1=(8.794)/(f*sqrt(er)) % effective radius in centimeters
ae=a*sqrt(1+(2*h/(pi*a*er)*((log(a/(2*h)))+(1.41*er+1.77)+(h/a)*(0.268*er+1.65)))) % same effective radius and must be = ae1 to get the true radius a from the equation
lg=6*h+2*a %ground length
wg=lg %ground width
lf=0.49*l0 %feedline length
A=(z/60)*(((er+1)/2)^(1/2))+((er-1)/(er+1))*(0.23+(0.11/er));
wf=(8*h*exp(A))/((exp(2*A))-2) %feedline width

%units are in cm
----------------------------------------------------------------------

The Matlab Results :
-------------------

a =

1.7519 cm = 17.519 mm = circular patch radius


ae1 =

1.8633 cm


ae =

1.8633 cm


lg =

4.4638 cm = 44.638 mm = ground length . Hint: u might need to increase its value. so the new lg will equal to lf+2a+1mm= 42+ (2*17.519) +1mm= 78.038 mm ;))) any service buddy


wg =

4.4638 cm = 44.638 mm


lf =

4.2000 = 42 mm


wf =

0.3059=3.059 mm


----------------------------------------------------

h=1.6mm, circular patch radius= a = 17.519 mm, ----------------------------------------------------



Kind Regards,
urs,
Abdelmoniem Mowafak El-Assar

can u send me the code for finding the return loss ,directivity,return loss and radiation pattern.thanx in advance.