电荷灵敏放大器的原理看不懂

文献上写的The fundamental concept behind charge-transfer amplification is to produce voltage gain by exploiting charge conservation amongst capacitive devices[1]. For a series connection of two capacitive elements in a system for which charge is conserved, the product of the voltage across the first element and its capacitance must equal the product of the voltage across the second element and its capacitance as shown in Eq. 1.
Csmall*Vsmall = Qsystem = Clarge*Vlarge (1)
不懂为什么会相等？请高手指教

加上那篇文献，我理解觉得电压趋于相等可以用水平衡来理解。但是两边的电荷相等是什么道理啊？

 A_Self-Biased_Charge-Transfer_Sense_Amplifier.pdf

但是两端电压只差两倍左右，电容差十倍，乘积怎么会相等？

中间的基板是共同的啊,所以只要这个节点对地寄生电容很小就满足那个公式,这不是挺好
理解?

还是不很理解，可能我钻进死胡同了，还是英语理解有误啊？是指Cdl*Vdl = Qsystem = Csa*Vsa