Re: [moved] Rectifier design with impedance matching ckt
时间:04-04
整理:3721RD
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A diode automatically adjusts its internal resistance, so that current and voltage obey its particular equation. Suppose you get 1 mA and 0.4V. Therefore the diode presents 400 ohms.
Suppose its 15mA and 0.5V. Then diode resistance is 33 ohms.
To improve efficiency your antenna ought to be a size and shape which picks up sufficient rf, so that it generates voltage high enough to overcome diode threshold voltage.
Suppose its 15mA and 0.5V. Then diode resistance is 33 ohms.
To improve efficiency your antenna ought to be a size and shape which picks up sufficient rf, so that it generates voltage high enough to overcome diode threshold voltage.
Thank you for the reply :)
Can you please check my circuit in ADS which I have attached in the previous post in the same thread and tell me the modifications / improvements required?