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如何根据工艺厂给的.clf文件写出antenna.tcl文件,不知下面的定义是否正确

时间:10-02 整理:3721RD 点击:

工艺厂给的.clf文件如下:

define _libId (dbGetCurrentLibId)

dbClearLibAntennaRules _libId

dbDefineAntennaRule _libId 5 2 600 0

dbAddAntennaLayerRule_libId 5 "M1" 600 '(0.159 0 600 7000)

dbAddAntennaLayerRule_libId 5 "M2" 600 '(0.159 0 600 7000)

dbAddAntennaLayerRule_libId 5 "M3" 600 '(0.159 0 600 7000)

dbAddAntennaLayerRule_libId 5 "M4" 600 '(0.159 0 600 7000)

dbAddAntennaLayerRule_libId 5 "M5" 600 '(0.159 0 8000 30000)

dbDefineAntennaRule _libId 2 2 0 20

dbAddAntennaLayerRule_libId 2 "MV1" 20 '(0.159 0 83.33 75)

dbAddAntennaLayerRule_libId 2 "MV2" 20 '(0.159 0 83.33 75)

dbAddAntennaLayerRule_libId 2 "MV3" 20 '(0.159 0 83.33 75)

dbAddAntennaLayerRule_libId 2 "MV4" 20 '(0.159 0 83.33 75)

本人写的antenna.tcl文件如下:

define_antenna_rule -mode 5 -diode_mode 2 -metal_ratio 600 -cut_ratio 0

define_antenna_layer_rule -mode 5 -layer "M1" -ratio 600 -diode_ratio {0.159 0 600 7000}

define_antenna_layer_rule -mode 5 -layer "M2" -ratio 600 -diode_ratio {0.159 0 600 7000}

define_antenna_layer_rule -mode 5 -layer "M3" -ratio 600 -diode_ratio {0.159 0 600 7000}

define_antenna_layer_rule -mode 5 -layer "M4" -ratio 600 -diode_ratio {0.159 0 600 7000}

define_antenna_layer_rule -mode 5 -layer "M5" -ratio 600 -diode_ratio {0.159 0 8000 30000}

define_antenna_rule -mode 2 -diode_mode 2-metal_ratio 20 -cut_ratio 0

define_antenna_layer_rule -mode 2 -layer "MV1" -ratio 20 -diode_ratio {0.159 0 83.33 75}

define_antenna_layer_rule -mode 2 -layer "MV2" -ratio 20 -diode_ratio {0.159 0 83.33 75}

define_antenna_layer_rule -mode 2 -layer "MV3" -ratio 20 -diode_ratio {0.159 0 83.33 75}

define_antenna_layer_rule -mode 2 -layer "MV4" -ratio 20 -diode_ratio {0.159 0 83.33 75}

问:(1)dbDefineAntennaRule _libId 5 2 600 0与dbDefineAntennaRule _libId 2 2 0 20中的数值分别对应define_antenna_rule、define_antenna_layer_rule中的哪个options?(2)我的antenna.tcl文件是否写正确?

dbDefineAntennaRule _libId 5 2 600 0与dbDefineAntennaRule _libId 2 2 0 20中的数值分别对应define_antenna_rule、define_antenna_layer_rule中的哪个options?求解疑

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