微波EDA网,见证研发工程师的成长!
首页 > 研发问答 > 微波和射频技术 > 天线设计和射频技术 > how to choose the charge pump current in PLL circuit design

how to choose the charge pump current in PLL circuit design

时间:04-06 整理:3721RD 点击:
Hello,

I use one PLL chip from ADI in my design and have a question on the charge pump current. Several current levels could be selected, from lower 0.6mA to higher 5mA. I verified and found that lower current will decrease the noise out-of band which seems to be better,I haven't found any performance deteriorated maybe due to my incompleted measurement.

Would you pls advise how to choose the charge pump current ,the lower the better or....thanks.

I guess it is a bandwidth thing. If you want a big bandwidth in the control loop, you want the highest output current. If you do not want a big control loop bandwidth, a lower current could be used. Bigger current should give you less susceptability to stray noise pickup. Battery operation--you would go with the low output current setting.

Thanks, you mean the bandwidth of loop filter, is it only decided by the loop filter itself design?

Yes, changing the current output from .5 to 5 mA is like putting an amplifier with a gain of 10 in the control loop filter. If you keep the other component values the same, you will get a bigger control loop bandwith with the 5 mA setting (~10x the bandwidth--see sketch of open loop gain change)

Changing the charge pump current will increase the bandwidth of the open loop response, but the affect on closed loop response is not so straightforward. A larger open loop gain may cause instability or excessive overshoot if the phase response is not also considered.

that is only true if there is some parasitic reactance in the load (like a big bypass capacitor to ground on a VCO tune line). For a VCO with not much parasitics, If you move the poles and zeros up in frequency (like in the sketch) there is NO impact on ringing/stability.

Right, you have to scale your compensation poles and zeros as well, which must be done by changing component values. Your sketch shows a zero actually being shifted in frequency, which does not happen as a result of changing charge pump current.

Sorry, sometimes I am not as clear as I intend to be. You are right, if you just up the gain without changing the Rs and Cs, you can make the loop unstable. You can do a little of a gain change and get away with it though.

Thanks to you all.

- - - Updated - - -

Thanks to you all.

上一篇:RF spectre software needed
下一篇:最后一页

Copyright © 2017-2020 微波EDA网 版权所有

网站地图

Top