微波EDA网,见证研发工程师的成长! 2025濠电姷鏁告慨鎾儉婢舵劕绾ч幖瀛樻尭娴滅偓淇婇妶鍕妽闁告瑥绻橀弻锝夊箣閿濆棭妫勭紒鐐劤濞硷繝寮婚悢鍛婄秶闁告挆鍛缂傚倷鑳舵刊顓㈠垂閸洖钃熼柕濞炬櫆閸嬪棝鏌涚仦鍓р槈妞ゅ骏鎷�04闂傚倸鍊搁崐鎼佸磹閹间礁纾瑰瀣捣閻棗銆掑锝呬壕濡ょ姷鍋為悧鐘汇€侀弴銏℃櫆闁芥ê顦純鏇㈡⒒娴h櫣甯涢柛鏃€娲熼獮鏍敃閵堝洣绗夊銈嗙墱閸嬬偤鎮¢妷鈺傜厽闁哄洨鍋涢埀顒€婀遍埀顒佺啲閹凤拷09闂傚倸鍊搁崐鎼佸磹閹间礁纾瑰瀣捣閻棗銆掑锝呬壕濡ょ姷鍋為悧鐘汇€侀弴銏℃櫇闁逞屽墰缁絽螖娴h櫣顔曢梺鐟扮摠閻熴儵鎮橀埡鍐<闁绘瑢鍋撻柛銊ョ埣瀵濡搁埡鍌氫簽闂佺ǹ鏈粙鎴︻敂閿燂拷 闂傚倸鍊搁崐鎼佸磹閹间礁纾瑰瀣捣閻棗銆掑锝呬壕濡ょ姷鍋為悧鐘汇€侀弴銏犖ч柛灞剧煯婢规洖鈹戦缁撶細闁告鍐f瀺鐎广儱娲犻崑鎾舵喆閸曨剛锛涢梺鍛婎殕婵炲﹪鎮伴鈧畷鍫曨敆婢跺娅屽┑鐘垫暩婵挳骞婃径鎰;闁规崘顕ч柨銈嗕繆閵堝嫯鍏岄柛娆忔濮婅櫣绱掑Ο鑽ゎ槬闂佺ǹ锕ゅ﹢閬嶅焵椤掍胶鍟查柟鍑ゆ嫹婵犵數濮烽弫鍛婃叏閻戣棄鏋侀柟闂寸绾惧鏌i幇顒佹儓闁搞劌鍊块弻娑㈩敃閿濆棛顦ョ紓浣哄Ь椤濡甸崟顖氱疀闁告挷鑳堕弳鐘电磽娴e搫顎岄柛銊ョ埣瀵濡搁埡鍌氫簽闂佺ǹ鏈粙鎴︻敂閿燂拷
首页 > 研发问答 > 微波和射频技术 > 电磁仿真讨论 > how to use CST MWS to calculate inductance by S-parameter of two kontaktlos coils

how to use CST MWS to calculate inductance by S-parameter of two kontaktlos coils

时间:03-26 整理:3721RD 点击:
i will simulate two kontaktlos coils, between is air.
simulate with the CST MWS to calculate mutual inductance between the coils and the respective self-inductance,

Primary coil: outer diameter 130mm, diameter 40mm, coil material: iron μr = 2300 Winding material: copper μr = 1, and the resistivity ρ = 0.0176Ωmm2 / m, the primary coil input current 10 A
Secondary coil: outer diameter 130mm, diameter 40mm, coil material: iron μr = 2300 Winding material: copper μr = 1, and the resistivity ρ = 0.0176Ωmm2 / m

Between primary and secondary air spacing 30mm.
better using S-parameter.

the model is :
Attachment 58222Attachment 58223
Attachment 58223 given formular: Main inductance LH = N12*f1/I1 I
Primary inductance L1s = N12*(f1-f2)/I1
secondary inductance L2s = N22*(f2-f1)/I2

how i could calculate inductance from S-parameter?
thanks

The problem is how to add a current souce inside one coil and the relationship between S-parameter and inductance.
Thanks in advance.

Anyone could help?

Copyright © 2017-2020 微波EDA网 版权所有

网站地图

Top