16乘8点阵滚动问题

时间：10-02 整理：3721RD 点击：

用p1口进行列扫描
用p0和p2配合使用两个74LS373控制（通过p2.1和p2.0选择其中之一）右边的十六个接口                   让点阵从左向右滚动显示汉字，为什么                                                       ORG 0100H    SETB TR0
   MOV SP,#30H
   CLR  PSW.7
   SETB TR0
   MOV TMOD,#02H
   MOV TL0,#156
   MOV TH0,#156
   MOV P0,#255
   SETB P2.1
   CLR P2.0
   MOV P1,#1
   MOV DPTR,#L4
   MOV A,#0
      MOV R3,A
   ORG 0300H
   L1: MOVC A,@A+DPTR
   MOV P0,A
   NOP
   NOP
   NOP
   NOP
   NOP
   NOP
   NOP
   NOP
   NOP
   NOP
   MOV A,R3
   INC A
   MOV R3,A
   INC R2
   MOV P0,#255
   CPL P2.0
   CPL P2.1
   CJNE R2,#2,L1
   MOV R2,#0
   MOV A,P1
   RLC A
   MOV P1,A
   MOV A,R3
   JNC L1
   MOV A,#0
   MOV R3,A
   MOV A,P1
   RLC A
   MOV P1,A
   MOV A,R3
   jb tf0,l2
   LJMP L1
   L2: CLR TF0
   INC R4
CJNE R4,#100,L3
MOV R4,#0
INC R5
CJNE R5,#5,L3
MOV R5,#0
INC R6
MOV 00H,C
MOV 31H,A
      MOV A,DPL
      ADD A,#02H
MOV DPL,A
MOV A,DPH
ADDC A,#0
MOV DPH,A
MOV C,00H
MOV A,31H
CJNE R6,#48,L3
MOV R6,#0
MOV DPTR,#L4
LJMP L1
   L3:LJMP L1

   L4:
DB 0FFH ,0FEH ,0FEH, 0F9H ,0EEH, 83H ,0EEH ,0A7H ,80H, 0F3H ,80H, 03H ,0EEH, 0D9H ,0EEH, 0DDH;
DB 0FEH ,0EDH ,0CFH, 0CDH ,0F3H ,9DH ,0F8H, 3DH ,0F0H ,3DH ,0C7H ,8DH ,0DFH ,0EDH ,0FFH ,0FFH;"赵",0
DB 0FFH ,0FFH ,0FFH ,0FDH ,0C0H, 19H ,0DFH ,0E3H ,0D0H ,0FH ,0DFH ,0E7H ,0C0H, 13H ,0FFH, 0EBH;
DB 0F3H ,0E7H ,0F3H ,0CFH ,0F3H ,3FH ,0F0H ,0FDH, 80H ,01H ,0F3H, 0FFH ,0F3H ,0FFH, 0F3H ,0FFH;"财",1
DB 0FFH ,0FFH ,0D8H ,7FH ,0D8H ,7DH ,0DBH ,7DH ,0C3H ,01H ,0C3H ,0FFH ,0FFH ,0FDH, 86H ,0DH;
DB 0B6H ,0DDH ,0B6H ,0DDH ,0B0H ,03H ,0B6H ,0DBH ,0B6H ,0DBH, 86H, 13H ,0FFH ,0F9H ,0FFH ,0FFH;"强",2
db 0FFH ,0FFH, 0FEH ,0F9H, 0EEH ,83H, 0EEH ,0A7H, 80H ,0F3H, 80H ,03H, 0EEH ,0D9H ,0EEH ,0DDH;
END

这一个代码可以实现，而

ORG 0000H
LJMP 0100H
ORG 000BH
LJMP L2
ORG 0100H
SETB EA
SETB ET0
SETB TR0
MOV SP,#30H
CLR PSW.7
SETB TR0
MOV TMOD,#02H
MOV TL0,#156
MOV TH0,#156
MOV P0,#255
SETB P2.1
CLR P2.0
MOV P1,#1
MOV DPTR,#L4
MOV A,#0
MOV R3,A
ORG 0300H
L1: MOVC A,@A+DPTR
MOV P0,A
NOP
NOP
NOP
NOP
NOP
NOP
NOP
NOP
NOP
NOP
MOV A,R3
INC A
MOV R3,A
INC R2
MOV P0,#255
CPL P2.0
CPL P2.1
CJNE R2,#2,L1
MOV R2,#0
MOV A,P1
RLC A
MOV P1,A
MOV A,R3
JNC L1
MOV A,#0
MOV R3,A
MOV A,P1
RLC A
MOV P1,A
MOV A,R3
LJMP L1
L2:
INC R4
CJNE R4,#100,L3
MOV R4,#0
INC R5
CJNE R5,#5,L3
MOV R5,#0
INC R6
MOV 00H,C
MOV 31H,A
MOV A,DPL
ADD A,#02H
MOV DPL,A
MOV A,DPH
ADDC A,#0
MOV DPH,A
MOV C,00H
MOV A,31H
CJNE R6,#48,L3
MOV R6,#0
MOV DPTR,#L4
RETI
L3:RETI
L4:
DB 0FFH ,0FEH ,0FEH, 0F9H ,0EEH, 83H ,0EEH ,0A7H ,80H, 0F3H ,80H, 03H ,0EEH, 0D9H ,0EEH, 0DDH;
DB 0FEH ,0EDH ,0CFH, 0CDH ,0F3H ,9DH ,0F8H, 3DH ,0F0H ,3DH ,0C7H ,8DH ,0DFH ,0EDH ,0FFH ,0FFH;"赵",0
DB 0FFH ,0FFH ,0FFH ,0FDH ,0C0H, 19H ,0DFH ,0E3H ,0D0H ,0FH ,0DFH ,0E7H ,0C0H, 13H ,0FFH, 0EBH;
DB 0F3H ,0E7H ,0F3H ,0CFH ,0F3H ,3FH ,0F0H ,0FDH, 80H ,01H ,0F3H, 0FFH ,0F3H ,0FFH, 0F3H ,0FFH;"财",1
DB 0FFH ,0FFH ,0D8H ,7FH ,0D8H ,7DH ,0DBH ,7DH ,0C3H ,01H ,0C3H ,0FFH ,0FFH ,0FDH, 86H ,0DH;
DB 0B6H ,0DDH ,0B6H ,0DDH ,0B0H ,03H ,0B6H ,0DBH ,0B6H ,0DBH, 86H, 13H ,0FFH ,0F9H ,0FFH ,0FFH;"强",2
db 0FFH ,0FFH, 0FEH ,0F9H, 0EEH ,83H, 0EEH ,0A7H, 80H ,0F3H, 80H ,03H, 0EEH ,0D9H ,0EEH ,0DDH;
END

复制代码

就不能，只是一行一行的线，小白不懂为什么用查询方式可以，用中断方式就不行呢，自学不容易啊，第一次做按自己思路来的，找半天错误啦，没找着，只能依仗大家了，大神快来吧

来人啊

解决了，采用中断时由于返回原位可能由于比较转移指令影响cy，而采用查询时每次返回开始的地方，使cy重新清零，好像是这么个原因，

不是好像本身就是

程序结构不好，进中断，却不做必要的保护，不是好习惯。

受教受教，自学可能路子有点野

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