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a 4-way Wilkinson power divider with two sections

时间:04-05 整理:3721RD 点击:
hi guys
now am designing a Wilkinson power divider with two sections,first i designed a simple one-section and got a good simulation results,but when i added a section,obtained a bad results.also my three isolation resistors is 100ohm(if it is not wrong),then i don't know how to calculate the resistor(→two sevtions quarter wave length),so can anybody help me how to do it or give me some link about it .my design and simulation is in ADS2009.my index as folloiws:
1)ferqucncy 2-3Ghz. 2)return loss is less then -20db.3)mutual isolation is less then -20db. 4)VSWR of input and output is less then 1.5(of course my oputput is less then 1.1 and i hope my input is 1.3 best altuough its 1.5 now)
thnx in advance.

In the image attached can see an n-port Wilkinson and the equations for the resistor and line impedance values, for various input/output port impedances.
Check how the resistors are connected one to each other.

hi vfone
thnx for ur help,but the picture u uploded is only one section and i know it whih the equation Z0=squareZ1*Z2,now my question is that i don't know how to calculate line impedance values with two sections.and i had read the book "Microwave and RF Wireless Systems"by David M.Pozar,in the section 5 i found the table 5.2,am noy completely sure if this table can be used to design Wilkinson power divider.ty in advance.

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