Relationship of dBm Input Power and Input RF Sinusoidal Signal

I have read a paper that states, "The optimized rectifier achieves 83.3 % power conversion efficiency (PCE) at -16.3 dBm input power, with an input RF of 953 MHz and 0.6 V peak sinusoidal signal." My question is, how did he get the value 0.6 V peak from the given input power of -16.3dBm?

I have read a formula that we can use
PdBm=10log(Pwatt/1mW)
Pwatt= vrms2/R

But if we solve the given values using the formula, we get:
-16.3=10log(Pwatt/1mW)
Pwatt=23.44uW
23.44uW= vrms2/R (say antenna impedance is 50 Ohms)
vrms=0.034
vpeak=vrms*√2 = 48mV

Where does 0.6 V peak come from?

We are designing a rectifier whose RF input signals will be coming from the harvested WiFi energy. Our problem is how to generate these RF inputs from the given input power measured at the feedpoint of the antenna, say -21dBm RF input power.

Thank you all for your help.

Show us "paper".

Can you understand Peak-Envelope-Power(PEP) and Averarged-Power ?

Evaluate cresto-factor of Wifi signal over long time.
Then apply cresto-factor for setting avaraged power.
If you don't want to apply cresto-factor, build APC(Auto Power Control) Loop by behavioral mode.
Here you have to understand power detector's characteristics enoughly.
Can you understand APC Loop ?

Learn actual signal generator.

By putting that phrase into google search:
http://hobbydocbox.com/Radio/7781005...lications.html

My best guess is that they use the matching network to transform from 50 Ohm antenna impedance to higher impedance level, for higher input voltage.

I know this paper.

They use ideal differential voltage drive. Here there is no signal source impedance.
And there is no matching.

Input Power is defined by real(Vfund*conj(Ifund))/2. |Vfund|=|Vpeak|=0.6V
|Ifund| is very small.

See followings.
https://www.edaboard.com/showthread.php?360833#8
https://www.edaboard.com/showthread.php?368055

Wow. If they claim operation at input power xx dBm, that implies you need impedance matching from the antenna impedance to that impedance level. Didn't they care about that aspect? In a practical application, that matching would cost efficiency, so it's somewhat theoretical to leave it out.

And I'm afraid much of these RF energy harvesting projects are VERY optimistic regarding input power levels.

Exactly, -12 or -20dbm Power is no joke in RF, most of Radar or Wi-fi applications use power as low as -90~100dbm; I have no idea where they will find these power levels in a normal environment unless they place it right near a GSM tower I dunno.

Moreover, most of commmercial/industrial transceivers have some kind of Automated-Gain Control to control the output power for their own efficiency and technical regulations(the ones I design have as far as Im concerned)

Sensitivity point of UHF RFID tag is around -20dBm.

That is more an exception, because that is a system designed to power components by incident field.

It seems you don't know UHF RFID system.

http://www.farsens.com/en/products/rocky100/

http://www.powercastco.com/wp-conten...calculator.xls

What's your point?

For RFID, we illuminate the target area with enough RF level to power the tags, at appropriate duty cycle.

But looking at all these power harvesting threads, it seems that people want to use Wifi and cellular as the power source. If I measure the Wifi levels in my office, that's around -50 to -60dBm one door away from the base station. And much less if I move a few more meters.

Here's the paper I am referring to. ---->https://sci-hub.tw/10.1109/ISMS.2016.59

It is stated in the abstract of this paper that:

"The optimized rectifier achieves 83.3 % power conversion efficiency (PCE) at -16.3 dBm input power, with an input RF of 953 MHz and 0.6 V peak sinusoidal signal. The voltage conversion ratio becomes 72.3 % at -13 dBm input power. The output average voltage equals 0.4 V at peak input voltage 0.6 V, whereas the conventional DDR rectifier achieves PCE = 75.4 % at an RF input power Pin = -12.5 dBm and output average voltage of 0.15 V at the same peak input voltage."

At different RF input power (-16.3dBm, -13dBm, and -12.5dBm), the peak input voltage stays the same (0.6V peak sinusoidal signal). I thought the RF input power affects the RF input voltage for the rectifier.

It is very natural result, since rectifier is drived by ideal differential voltage source.

Surely uunderstand https://www.edaboard.com/showthread.php?379647#4.

Not always.

Surely consider power equation in https://www.edaboard.com/showthread.php?379647#4

You have to consider phase difference of voltage and current.
If phase difference of voltage and current is 90degree, power is zero for any voltage value.

BTW, answer my question in https://www.edaboard.com/showthread.php?379588#2