单片机控制2轮电机，红色部分显示错误

#include<reg52.h>

#define Lg {P1^4=1,P1^5=0,P1^6=1,P1^7=0;} //左边2个电机前是前电机

#define Lb{P1^4=0,P1^5=1,P1^6=0,P1^7=1;} //左后

#define Ls {P1^4=0,P1^5=0,P1^6=0,P1^7=0;}

#define Rg {P1^4=1, P1^5=1,P1^6=1, P1^7=1;}

#define Rb {P1^4=0,P1^5=0,P1^6=0,P1^7=1;}

#define Rs {P1^4=0,P1^5=0,P1^6=0,P1^7=0;}

sbit S1=P1^4 ;

sbit S2=P1^5 ;

sbit S3=P1^6 ;

sbit S4=P1^7 ;

sbit S5=P1^4 ;

sbit S6=P0^7;

sbit S16=P0^6 ;

sbit S15=P0^5;

sbit S14=P0^4 ;

void delay(unsigned int k)

{

unsigned int x,y;

for(x=0;x<k;x++);

for(y=0;y<2000;y++);

}

void run(void)

{

Lg;

Rg;

}

void backrun(void)

{

Lb;

Rb;

}

void leftrun(void)

{

Lb;

Rg;

}

void rightrun(void)

{

Lg;

Rb;

}

void stoprun(void)

{

Ls;

Rs;

}

void main(void)

{

while(1)

{

if(P0^7==1&&P0^6==0)

{run();    }

if(P0^6==1&&P0^7==0)

{backrun();}

if(P0^5==1)

{leftrun();}

if(P0^4==1)

{rightrun(); }

if(P0^7==1&&P0^6==1)

{

stoprun();

}

那个宏定义中可以用总线赋值试下，如P1=0x01