经典IC设计面试问题10
时间：10-02
整理：3721RD
点击：
Given the following Verilog code, what value of "a" is displayed?
always @(clk) begin
a = 0;
a <= 1;
$display(a);
end
This is a tricky one！ Verilog scheduling semantics basically imply a
four-level deep queue for the current simulation time:
1: Active Events (blocking statements)
2: Inactive Events (#0 delays, etc)
3: Non-Blocking Assign Updates (non-blocking statements)
4: Monitor Events ($display, $monitor, etc).
Since the "a = 0" is an active event, it is scheduled into the 1st "queue".
The "a <= 1" is a non-blocking event, so it's placed into the 3rd queue.
Finally, the display statement is placed into the 4th queue. Only events in the active queue are completed this sim cycle, so the "a = 0" happens, and then the display shows a = 0. If we were to look at the value of a in the next sim cycle, it would show 1.
always @(clk) begin
a = 0;
a <= 1;
$display(a);
end
This is a tricky one！ Verilog scheduling semantics basically imply a
four-level deep queue for the current simulation time:
1: Active Events (blocking statements)
2: Inactive Events (#0 delays, etc)
3: Non-Blocking Assign Updates (non-blocking statements)
4: Monitor Events ($display, $monitor, etc).
Since the "a = 0" is an active event, it is scheduled into the 1st "queue".
The "a <= 1" is a non-blocking event, so it's placed into the 3rd queue.
Finally, the display statement is placed into the 4th queue. Only events in the active queue are completed this sim cycle, so the "a = 0" happens, and then the display shows a = 0. If we were to look at the value of a in the next sim cycle, it would show 1.
多谢小编分享！
你只要不这么写就可以了