经典IC设计面试问题11
时间：10-02
整理：3721RD
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Why is it that "if (2'b01 & 2'b10)..." doesn't run the true case?
This is a popular coding error. You used the bit wise AND operator (&) where you meant to use the logical AND operator (&&).
This is a popular coding error. You used the bit wise AND operator (&) where you meant to use the logical AND operator (&&).
有错误的
先收下再看
看了开头貌似还行~
没看到资料?
呵呵，看看
呵呵，这个比较简单啊