求助，编译报错

编译报错如下：
sum of the widths of these concatenate operands is not equal to the width of the result
请问是何原因?
谢谢
源程序如下：
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
use ieee.std_logic_arith.all;
entity a1 is
port(clk: in std_logic;
n: in std_logic;
x: in std_logic_vector(11 downto 0);
y1: out std_logic_vector(11 downto 0);
y2: out std_logic_vector(11 downto 0));
end a1;
architecture dd1 of a1 is
signal p0,p1,p2,p3,p4,p5,p6,p7,p8,p9,p10,p11,p12:std_logic_vector(11 downto 0);
begin
a: process(n)
variable s: integer range 0 to 14;
begin
if (n'event and n='1') then
case s is
when 0=>
p0<=not x(11)&x(10 downto 0);
s:=s+1;
when 1=>
p1<=not x(11)&x(10 downto 0);
s:=s+1;
when 2=>
p2<=not x(11)&x(10 downto 0);
s:=s+1;
when 3=>
p3<=not x(11)&x(10 downto 0);
s:=s+1;
when 4=>
p4<=not x(11)&x(10 downto 0);
s:=s+1;
when 5=>
p5<=not x(11)&x(10 downto 0);
s:=s+1;
when 6=>
p6<=not x(11)&x(10 downto 0);
s:=s+1;
when 7=>
p7<=not x(11)&x(10 downto 0);
s:=s+1;
when 8=>
p8<=not x(11)&x(10 downto 0);
s:=s+1;
when 9=>
p9<=not x(11)&x(10 downto 0);
s:=s+1;
when 10=>
p10<=not x(11)&x(10 downto 0);
s:=s+1;
when 11=>
p11<=not x(11)&x(10 downto 0);
s:=s+1;
when 12=>
p12<=not x(11)&x(10 downto 0);
s:=s+1;
when others =>
null;
end case;
end if;
end process a;
b1:process(clk)
variable q0,q1,q2,q3,q4,q5,q6,q7,q8,q9,q10,q11,q12:std_logic_vector(11 downto 0);
variable ta1,ta2,ta22,ta3,tb1,tb2,tb22,tb3,ya,yb:std_logic_vector(11 downto 0);
begin
if (clk'event and clk='1') then
q0:=p0;
q1:=p1;
q2:=p2;
q3:=p3;
q4:=p4;
q5:=p5;
q6:=p6;
q7:=p7;
q8:=p8;
q9:=p9;
q10:=p10;
q11:=p11;
q12:=p12;
ta1:=q0+q12;
ta1:=ta1-q6;
ta2:=q1+q11;
ta2:=ta2-q5;
ta2:=ta2-q7;
ta22:=ta2(11)&ta2(11 downto 1);
ta22:=ta22+ta2(11)&ta2(11)&ta2(11 downto 2);
ta22:=ta22+ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11 downto 4);
ta22:=ta22+ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11 downto 5);
ta22:=ta22+ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11 downto 6);
ta22:=ta22+ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11 downto 8);
ta22:=ta22+ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11)&ta2(11 downto 9);
ta3:=q2+q10;
ta3:=ta3-q4;
ta3:=ta3-q8;
ta3:=ta3(11)&ta3(11 downto 1);
ya:=ta1+ta22;
ya:=ya+ta3;
y1<=ya;
tb1:=q1+q5;
tb1:=tb1-q7;
tb1:=tb1-q11;
tb1:=tb1(11)&tb1(11 downto 1);
tb2:=q2+q4;
tb2:=tb2-q8;
tb2:=tb2-q10;
tb22:=tb2(11)&tb2(11 downto 1);
tb22:=tb22+tb2(11)&tb2(11)&tb2(11 downto 2);
tb22:=tb22+tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11 downto 4);
tb22:=tb22+tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11 downto 5);
tb22:=tb22+tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11 downto 6);
tb22:=tb22+tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11 downto 8);
tb22:=tb22+tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11)&tb2(11 downto 9);
tb3:=q3-q9;
yb:=tb1+tb22;
yb:=yb+tb3;
y2<=yb;
end if;
end process b1;
end dd1;

求助，编译报错
前边是一位的,后边是12位的,可以按位相与么?