TDMA的帧号是以3h 28min 53s 760ms(271564.8个TDMA...
时间:12-25
整理:3721RD
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如题。
3h 28min 53s 760ms怎么理解?谢谢了!
3h 28min 53s 760ms怎么理解?谢谢了!
1时隙=156.25bit=0.577ms
1TDMA帧=8时隙=1250bit=4.616ms
26复帧=26TDMA帧=32500bit=120.016ms
51复帧=51TDMA帧=63750bit=235.416ms
1超帧=1326TDMA帧=51*26复帧=26*51复帧=1657500bit=6120.816ms
1超高帧=2048超帧=2715648TDMA帧=3394560000bit=12535431.168ms=3h28min53s760ms
TDMA帧号是以一个超高帧为周期循环编号
1ts=156.25bit=0.577ms
一个超帧=26*51帧
一个超高帧=2048超帧=2048*26*51=2715648帧=3h 28min 53s 760ms