115.2K串行通信C语言示例

//115.2k串行口通信程序，校验方式为简单双向校验,
//而且是必要的，因为任何采用中断、crc等的方法
//均很难保证速度和避免错误.
//总体速度5KB/秒

//单片机程序
//使用22.1184晶振
unsigned char time,b_break,b_break_3;
//35.555ms
void int_t0(void) interrupt 1 {
TH0=0;
if ((++b_break_3)>2) b_break=1;
time++;
}

//

unsigned char rec(void) {
TH0=0;b_break_3=0;b_break=0;
while (RI==0) {
if (b_break) return(1); //等待pc发送100ms超时
}
RI=0;
SBUF=SBUF;
return(SBUF);
}
/*返回1表示失败*/
bit sen(unsigned char d) {
SBUF=d;
TH0=0;b_break_3=0;b_break=0;
while (RI==0) {
if (b_break) return(1); //等待pc送回相同字节数据，100ms超时
}
RI=0;
if (SBUF!=d) return(1);
return(0);
}

void main(void) {
unsigned int i;
unsigned char d;
EA=1;
SCON=0xd8;PCON=0x80;
TMOD=0x21;
TL1=TH1=0xff;TR1=1;
TH0=0;ET0=TR0=1;
while (1) {
d=rec();
if ((!b_break)(d==0x55)) {
d=rec();
if (!b_break) {
if (d==0xaa) {
//接收到pc送来的要求发送指令0xaa55
for (i=0;i1000;i++) {
if (sen(i)) {
//发送错误
break;
}
}
} else if (dd==0xaa) {
//接收到pc送来的要求接收指令0xaaaa
for (i=0;i1000;i++) {
d=rec();
if (!b_break) {
//正确接收处理
} else {
//接收错误处理
break;
}
}
}
}
}
}
}

//电脑程序tc2.0
＃i nclude stdio.h
＃i nclude dos.h
＃i nclude process.h
＃i nclude string.h
＃i nclude conio.h
＃i nclude dir.h>

unsigned char time_out;

void init_com1(void) {
outportb(0x3fb,0x80);
outportb(0x3f8,1);
outportb(0x3f9,0x0);
outportb(0x3fb,0x3);
}
void sen_com1(unsigned char d) {
long i;
time_out=0;
while (!(inportb(0x3fd)0x20));
outportb(0x3fd,0x0);
outportb(0x3f8,d);
i=clock();
while (1) {
if (clock()>(i+8)) {time_out=1;return;}
if ((inp(0x3fd)0x1)==1) break;
}
if (inp(0x3f8)!=d) {time_out=2;return;}
}
unsigned char rec_com1(void) {
long i;
unsigned char d;
time_out=0;
i=clock();
while (1) {
if (clock()>(i+8)) {time_out=1;return(0);}
if ((inp(0x3fd)1)==1) break;
}
d=inp(0x3f8);
while (!(inportb(0x3fd)0x20));
outportb(0x3fd,0x0);
outportb(0x3f8,d);
return(d);
}
void main(void) {
int i;
long st;
init_com1();
st=clock();
sen_com1(0xaa);
if (time_out) {printf(CPU not ready!);exit(-1);}
sen_com1(0xaa);
if (time_out) {printf(CPU not ready!);exit(-1);}
for (i=0;i1000;i++) {
sen_com1(i);
if (time_out) {printf(CPU not ready!);exit(-1);}
}
printf(Total use %3.2f S.,(clock()-st)/18.2);
exit(1);
}