MPU6050卡尔曼滤波C语言实现函数参数是哈意思?
时间:10-02
整理:3721RD
点击:
以下是实现的函数,但是n,m,k,f,q,r,h,y,x,p,g 这些参数是什么,哪位大神给讲讲
#include "stdlib.h"
#include "rinv.c"
int lman(n,m,k,f,q,r,h,y,x,p,g)
//int n,m,k;
//double f[],q[],r[],h[],y[],x[],p[],g[];
{
int i,j,kk,ii,l,jj,js;
double *e,*a,*b;
e=malloc(m*m*sizeof(double));
l=m;
if (l<n)
l=n;
a=malloc(l*l*sizeof(double));
b=malloc(l*l*sizeof(double));
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
ii=i*l+j; a[ii]=0.0;
for (kk=0; kk<=n-1; kk++)
a[ii]=a[ii]+p[i*n+kk]*f[j*n+kk];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
ii=i*n+j; p[ii]=q[ii];
for (kk=0; kk<=n-1; kk++)
p[ii]=p[ii]+f[i*n+kk]*a[kk*l+j];
}
for (ii=2; ii<=k; ii++)
{
for (i=0; i<=n-1; i++)
for (j=0; j<=m-1; j++)
{
jj=i*l+j; a[jj]=0.0;
for (kk=0; kk<=n-1; kk++)
a[jj]=a[jj]+p[i*n+kk]*h[j*n+kk];
}
for (i=0; i<=m-1; i++)
for (j=0; j<=m-1; j++)
{
jj=i*m+j; e[jj]=r[jj];
for (kk=0; kk<=n-1; kk++)
e[jj]=e[jj]+h[i*n+kk]*a[kk*l+j];
}
js=rinv(e,m);
if (js==0)
{
free(e);
free(a);
free(b);
return(js);
}
for (i=0; i<=n-1; i++)
for (j=0; j<=m-1; j++)
{
jj=i*m+j; g[jj]=0.0;
for (kk=0; kk<=m-1; kk++)
g[jj]=g[jj]+a[i*l+kk]*e[j*m+kk];
}
for (i=0; i<=n-1; i++)
{
jj=(ii-1)*n+i; x[jj]=0.0;
for (j=0; j<=n-1; j++)
x[jj]=x[jj]+f[i*n+j]*x[(ii-2)*n+j];
}
for (i=0; i<=m-1; i++)
{
jj=i*l; b[jj]=y[(ii-1)*m+i];
for (j=0; j<=n-1; j++)
b[jj]=b[jj]-h[i*n+j]*x[(ii-1)*n+j];
}
for (i=0; i<=n-1; i++)
{
jj=(ii-1)*n+i;
for (j=0; j<=m-1; j++)
x[jj]=x[jj]+g[i*m+j]*b[j*l];
}
if (ii<k)
{
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*l+j; a[jj]=0.0;
for (kk=0; kk<=m-1; kk++)
a[jj]=a[jj]-g[i*m+kk]*h[kk*n+j];
if (i==j) a[jj]=1.0+a[jj];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*l+j; b[jj]=0.0;
for (kk=0; kk<=n-1; kk++)
b[jj]=b[jj]+a[i*l+kk]*p[kk*n+j];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*l+j; a[jj]=0.0;
for (kk=0; kk<=n-1; kk++)
a[jj]=a[jj]+b[i*l+kk]*f[j*n+kk];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*n+j; p[jj]=q[jj];
for (kk=0; kk<=n-1; kk++)
p[jj]=p[jj]+f[i*n+kk]*a[j*l+kk];
}
}
}
free(e);
free(a);
free(b);
return(js);
}
#include "stdlib.h"
#include "rinv.c"
int lman(n,m,k,f,q,r,h,y,x,p,g)
//int n,m,k;
//double f[],q[],r[],h[],y[],x[],p[],g[];
{
int i,j,kk,ii,l,jj,js;
double *e,*a,*b;
e=malloc(m*m*sizeof(double));
l=m;
if (l<n)
l=n;
a=malloc(l*l*sizeof(double));
b=malloc(l*l*sizeof(double));
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
ii=i*l+j; a[ii]=0.0;
for (kk=0; kk<=n-1; kk++)
a[ii]=a[ii]+p[i*n+kk]*f[j*n+kk];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
ii=i*n+j; p[ii]=q[ii];
for (kk=0; kk<=n-1; kk++)
p[ii]=p[ii]+f[i*n+kk]*a[kk*l+j];
}
for (ii=2; ii<=k; ii++)
{
for (i=0; i<=n-1; i++)
for (j=0; j<=m-1; j++)
{
jj=i*l+j; a[jj]=0.0;
for (kk=0; kk<=n-1; kk++)
a[jj]=a[jj]+p[i*n+kk]*h[j*n+kk];
}
for (i=0; i<=m-1; i++)
for (j=0; j<=m-1; j++)
{
jj=i*m+j; e[jj]=r[jj];
for (kk=0; kk<=n-1; kk++)
e[jj]=e[jj]+h[i*n+kk]*a[kk*l+j];
}
js=rinv(e,m);
if (js==0)
{
free(e);
free(a);
free(b);
return(js);
}
for (i=0; i<=n-1; i++)
for (j=0; j<=m-1; j++)
{
jj=i*m+j; g[jj]=0.0;
for (kk=0; kk<=m-1; kk++)
g[jj]=g[jj]+a[i*l+kk]*e[j*m+kk];
}
for (i=0; i<=n-1; i++)
{
jj=(ii-1)*n+i; x[jj]=0.0;
for (j=0; j<=n-1; j++)
x[jj]=x[jj]+f[i*n+j]*x[(ii-2)*n+j];
}
for (i=0; i<=m-1; i++)
{
jj=i*l; b[jj]=y[(ii-1)*m+i];
for (j=0; j<=n-1; j++)
b[jj]=b[jj]-h[i*n+j]*x[(ii-1)*n+j];
}
for (i=0; i<=n-1; i++)
{
jj=(ii-1)*n+i;
for (j=0; j<=m-1; j++)
x[jj]=x[jj]+g[i*m+j]*b[j*l];
}
if (ii<k)
{
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*l+j; a[jj]=0.0;
for (kk=0; kk<=m-1; kk++)
a[jj]=a[jj]-g[i*m+kk]*h[kk*n+j];
if (i==j) a[jj]=1.0+a[jj];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*l+j; b[jj]=0.0;
for (kk=0; kk<=n-1; kk++)
b[jj]=b[jj]+a[i*l+kk]*p[kk*n+j];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*l+j; a[jj]=0.0;
for (kk=0; kk<=n-1; kk++)
a[jj]=a[jj]+b[i*l+kk]*f[j*n+kk];
}
for (i=0; i<=n-1; i++)
for (j=0; j<=n-1; j++)
{
jj=i*n+j; p[jj]=q[jj];
for (kk=0; kk<=n-1; kk++)
p[jj]=p[jj]+f[i*n+kk]*a[j*l+kk];
}
}
}
free(e);
free(a);
free(b);
return(js);
}
能不能将一下参数的含义