90 degree phase shifted magnetic fields

If we have a closed magnetic circuit with two primary coils and one secondary coil wound on it. The primary coils are wound such that unlike poles are adjacent. Both primary coils are using rectified AC and the current in one coil is phase shifted by 90 degrees to the other coil.

This would result in an interplay of the magnetic fields where one is increasing to its peak value while at the same time the other is decreasing to zero. What would be the effect of the magnetic fields on a secondary coil? If somebody is familiar with magnetic simulation software maybe you could model it.

Simple math. The sum of 90 degree phase shifted fields of same magnitude is a 45 degree shifted field.

As far as I correctly understand your question, the signals to the primary coil are rectified, that means they are A*|sin(wt)| and A*|sin(wt+90)| (I supposed same amplitude).
In this case the 45 degrees shift still apply, but the sum will have an amplitude going from A to sqrt(2)*A. This can be seen just applying the sum to the first 90 degrees (after the rectifier the frequency will double), then the waveform will repeat. In the first 90 degrees both sin(wt) and sin(Wt+90) are positive, then:

A*|sin(wt)| + A*|sin(Wt+90)| = A*sin(wt) + A*sin(wt+90)

Hi,

= A*sqrt(2)*sin(wt+45)

Klaus

The math is quite simple for the assumed (rectified) sine currents, but does the circuit actually generate sine current waveforms? This would be only the case with current sources.