偏执电流求解
图中电流镜偏置电路，不考虑体效应，问流过电阻R的电流是多少?大神稍微说明解释一下。
when the circuit achieve stable state, the current passing the resistor R is 20uA.
at the initial state, Pmos mirror sources40uA, while the Nmos mirror can only sink 20uA, so there is a net sourcing 20uA current charging to the parasitic capacitors of P/Nmos drain region. finally, the voltage on the upper node of the resistor raises, and push the PMOS to the linear region a bit, and make the sourcing ability weaker till 20uA, and then the balance is achieved.
“at the initial state, Pmos mirror sources40uA, while the Nmos mirror can only sink 20uA”有什么根据吗
Thanks。
俺仿了一下，最右PMOS确实没出现40A的情况。
红线为最右NMOS漏电流，黄线为最右PMOS源电流。
没电源大小，没R大小，怎么求，最高20μA，也可能低于。
it is an assumption, and it shows the conflict of the design.
A transient simulation can catch everything with the consideration of all the parasitic.
But the final conclusion will not change.
只可能20uA多一点 而且 PMOS处于线性区
很老的一个笔试题目了。
这个是某资料中的一个笔试题，具体就那么多参数。
学习啊学习，2楼写的很详细，就是英语的看着不习惯。
电流比较器，所以结果应该是10uA才对