电荷泵怎么跑出来电压主机减小呀？

It is hard to understand your question and read your plots. If you are wondering low output voltage at the output it is normal. Since you have 2V VDD and & diodes series your diode voltage drop at each step would left you with no extra voltage. Even if diodes are shotky type each diode will cause a loss of ~0.4V due to forward voltage drop each step. You will not have any voltage left at the end with that many diodes and 2V Vdd. You can derive it recursively by starting at first stage and going towards to output step by step.
Instead of dixon type with diodes you can implement diodes with MOS so you would have smaller voltage drop but you will need more components and good design for preventing Latch-up due to body voltage control requirement (also voltage loss due to extra capacitive parasitic).
There are many examples in the literature so I do not elaborate on this. Just search for "Dixon charge pump" on the internet.
这是很难理解你的问题，读你的阴谋。如果你想知道在低输出电压的输出，它是正常的。既然你有2V VDD和二极管系列二极管压降，在每一步离开你没有额外的电压。即使二极管shotky键入每个二极管会造成损失的～0.4V，由于正向压降的每一步。你不会有任何在最后留下了许多二极管和2V VDD电压。你可以得到它在第一阶段，并开始向输出一步一步去递归。而不是狄克逊与二极管的类型，您可以实现的MOS二极管，所以你将有较小的压降，但您将需要更多的组件和良好的设计，防止闭锁由于身体电压控制要求（电压损耗，由于额外的电容寄生）。有许多例子在文学，所以我不细说了。只是“迪克森电荷泵”在互联网上搜索。

谢谢 用SMIC的二极管就没问题 我想应该是UMC中二极管的的原因