关于此程序的解释 求大虾们帮助下 谢谢了
时间:10-02
整理:3721RD
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这是一个两点间温度控制程序 其中的数码显示段的一部分不太明白
#include <AT89X52.H>
unsigned char code dispbitcode[]={0xfe,0xfd,0xfb,0xf7,
0xef,0xdf,0xbf,0x7f};
unsigned char code dispcode[]={0x3f,0x06,0x5b,0x4f,0x66,
0x6d,0x7d,0x07,0x7f,0x6f,0x00};
unsigned char dispbuf[8]={10,10,10,10,10,10,0,0}; 这一行是什么意思 请解释一下好吗 具体点
unsigned char dispcount;
unsigned char getdata;
unsigned int temp;
unsigned char i;
sbit ST=P3^0;
sbit OE=P3^1;
sbit EOC=P3^2;
sbit CLK=P3^3;
sbit LED1=P3^6;
sbit LED2=P3^7;
sbit SPK=P3^5;
bit lowflag;
bit highflag;
unsigned int cnta;
unsigned int cntb;
bit alarmflag;
void main(void)
{
ST=0;
OE=0;
TMOD=0x12;
TH0=0x216;
TL0=0x216;
TH1=(65536-500)/256;
TL1=(65536-500)%256;
TR1=1;
TR0=1;
ET0=1;
ET1=1;
EA=1;
ST=1;
ST=0;
while(1)
{
if((lowflag==1) &&(highflag==0))
{
LED1=0;
LED2=1;
}
else if((highflag==1) && (lowflag==0))
{
LED1=1;
LED2=0;
}
else
{
LED1=1;
LED2=1;
}
}
}
void t0(void) interrupt 1 using 0
{
CLK=~CLK;
}
void t1(void) interrupt 3 using 0
{
TH1=(65536-500)/256;
TL1=(65536-500)%256;
if(EOC==1)
{
OE=1;
getdata=P0;
OE=0;
temp=getdata*25;//这两行是怎么来的 *25和temp/64; 程序分为三段0到30 度报警 30到60度没事 60到90度报警 模拟的电阻为0到7K 的
temp=temp/64;
i=6;
dispbuf[0]=10;
dispbuf[1]=10;
dispbuf[2]=10;
dispbuf[3]=10;
dispbuf[4]=10;
dispbuf[5]=10;
dispbuf[6]=0;
dispbuf[7]=0;
while(temp/10)
{
dispbuf=temp%10;
temp=temp/10;
i++;
}
dispbuf=temp;
if(getdata<77)
{
lowflag=1;
highflag=0;
}
else if(getdata>153)
{
lowflag=0;
highflag=1;
}
else
{
lowflag=0;
highflag=0;
}
ST=1;
ST=0;
}
P1=dispcode[dispbuf[dispcount]]; 这两行又怎么解释呢
P2=dispbitcode[dispcount];
dispcount++;
if(dispcount==8)
{
dispcount=0;
}
if((lowflag==1) && (highflag==0))
{
cnta++;
if(cnta==800)
{
cnta=0;
alarmflag=~alarmflag;
}
if(alarmflag==1)
{
SPK=~SPK;
}
}
else if((lowflag==0) && (highflag==1))
{
cntb++;
if(cntb==400)
{
cntb=0;
alarmflag=~alarmflag;
}
if(alarmflag==1)
{
SPK=~SPK;
}
}
else
{
alarmflag=0;
cnta=0;
cntb=0;
}
}
说实在的 应该学学编程习惯 加点注释会好点