问一个波形采集测量频率的问题
时间:12-13
整理:3721RD
点击:
正弦信号通过NI6024E采样
用Extract Single Tone Information 这一模块测量其频率
发现测量得到的值与真是的信号频率存在一定关系
即
测量值=实际频率×采样频率/1000
1000为默认的采样频率
有没有哪位使用这块板卡的
知道是什么原因照成的?
谢谢
.10
用Extract Single Tone Information 这一模块测量其频率
发现测量得到的值与真是的信号频率存在一定关系
即
测量值=实际频率×采样频率/1000
1000为默认的采样频率
有没有哪位使用这块板卡的
知道是什么原因照成的?
谢谢
.10
What is the frequency of your signal? By Nyquist samping theorem, the sampling
rate should be at least twice of the signal frequency. For better measurement
, you may set to five times or more.
By the way, given your euquition, I do not understand why 1000 is there. Howev
er, if the sampling rate is exactly 1000, you get the desired frequency anyway
.
.60