CST中算出的偶合系数怎么这么大，盼高手指点
时间：10-02
整理：3721RD
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Tchebychev Filter
===================
Order = 4
Bandwidth = 8 MHz
Passband ripple = 0.01 dB (1.100747 VSWR)
Return loss = -26.3828 dB
Normed g values:
-------------------------------------------
g1 = 0.7129
g2 = 1.2004
g3 = 1.3213
g4 = 0.6476
g5 = 1.1008
Corresponding coupling coefficients in MHz:
-------------------------------------------
k_E = 11.22
k1_2 = 8.65
k2_3 = 6.35
k3_4 = 8.65
k_out = 11.22
Group Delay Time
----------------
t_d1 = 56.727 ns
t_d2 = 95.519 ns
t_d3 = 161.87 ns
t_d4 = 147.054 ns
t_d5 = 224.313 ns
===================
Order = 4
Bandwidth = 8 MHz
Passband ripple = 0.01 dB (1.100747 VSWR)
Return loss = -26.3828 dB
Normed g values:
-------------------------------------------
g1 = 0.7129
g2 = 1.2004
g3 = 1.3213
g4 = 0.6476
g5 = 1.1008
Corresponding coupling coefficients in MHz:
-------------------------------------------
k_E = 11.22
k1_2 = 8.65
k2_3 = 6.35
k3_4 = 8.65
k_out = 11.22
Group Delay Time
----------------
t_d1 = 56.727 ns
t_d2 = 95.519 ns
t_d3 = 161.87 ns
t_d4 = 147.054 ns
t_d5 = 224.313 ns
你检查哈，结果第一个本征模的谐振频率是不是0哦?
我以前就出现过耦合系数大于1的情况，仔细看原来是谐振频率不对
简易你多加几个模式计算
或者用HFSS
非常感谢指点 上面数据是由后处理模板直接算出的，是归一化的吗?
Corresponding coupling coefficients in MHz:
-------------------------------------------
k_E = 11.22
k1_2 = 8.65
k2_3 = 6.35
k3_4 = 8.65
k_out = 11.22
用上面的值处以中心频率就是所需要的耦合系数了
非常感谢！