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SI反射仿真问题

时间:10-02 整理:3721RD 点击:
VIH overshoot: VIH,max = VDDQ + 1.2V for a pulse width ≤ 3ns, and the pulse width cannot
be greater than one-third of the cycle rate. VIL undershoot: VIL,min = –1.2V for a pulse
width ≤3ns, and the pulse width cannot be greater than one-third of the cycle rate.
大家是如何理解这段话的,比如供电电压为3.3V,是不是只要过冲电压小于4.5V,下冲电压大于-1.2V就可以了,我不大理解for a pulse width ≤ 3ns, and the pulse width cannot be greater than one-third of the cycle rate ,这句话是说的啥意思呢?

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